Two soap bubbles A and B are kept in a closed chamber where the air is maintained at pressure 8 N/m 2 . The radii of bubbles A and B are 2cm and 4cm, respectively. Surface tension of the soap-water used to make bubbles is 0.04 N/m. Find the ratio n B /n A , where n A and n B are the number of moles of air in bubbles A and B, respectively. [Neglect the effect of gravity.]
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
(6)
Sol. P A = P 0 + 
⇒ P A = 8 + 
P A = 16 N/m 2
P B = P 0 + 
= 8 + 
P B = 12 N/m 2
for bubble A, PV = nRT
(16) 
π (0.02) 3 = n A RT....
for bubble B
(12) 
= n B RT....
dividing eq n and 
; 
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